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== My New Hugo Site ==
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Katex

x2+1 \sqrt{x^2+1}
∑_i=1∞1n2=π26 \sum\_{i=1}^\infty\frac{1}{n^2}=\frac{\pi^2}{6}

When a≠0 a \ne 0 , there are two solutions to (ax2+bx+c=0)(ax^2 + bx + c = 0) and they are

x=−b±b2−4ac2a x = {-b \pm \sqrt{b^2-4ac} \over 2a}